v^2+25=-10v

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Solution for v^2+25=-10v equation: 



v^2+25=-10v

We move all terms to the left:

v^2+25-(-10v)=0

We get rid of parentheses

v^2+10v+25=0

a = 1; b = 10; c = +25;
Δ = b2-4ac
Δ = 102-4·1·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$v=\frac{-b}{2a}=\frac{-10}{2}=-5$

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